-36+4w^2=26w

Solution for -36+4w^2=26w equation:

-36+4w^2=26w

We move all terms to the left:

-36+4w^2-(26w)=0

a = 4; b = -26; c = -36;
Δ = b2-4ac
Δ = -262-4·4·(-36)
Δ = 1252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1252}=\sqrt{4*313}=\sqrt{4}*\sqrt{313}=2\sqrt{313}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{313}}{2*4}=\frac{26-2\sqrt{313}}{8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{313}}{2*4}=\frac{26+2\sqrt{313}}{8}
$